Let vector A = (6.0 m, 300 south of east), vector B = (13.9 m, north), vector C = (5.0 m, 450 south of west). Find the magnitude of vector D = A+B+C?

Answer 1

300 south of east?
that is 60 degrees short of all the way around to east again
maybe 30.0 ?
same with 450 south of west

Answer 2

My apologies, the degrees copied as zeroes. It's 30 degrees, 45 degrees.

Answer 3

ok
x is east
y is north

Ax = 6 cos 30
Ay = -6 sin 30

Bx = 0
By = 13.9

Cx = -5 cos 45
Cy = -5 sin 45

so
Dx = +6 cos 30 - 5 cos 45
Dy = -6 sin 30 + 13.9 -5 sin 45

|D| = sqrt (Dx^2 + Dy^2)

Answer 4

Thank you