The partial fractions part come to:
(3x2+x+9)/((x2+5)(x-6))
= 3/(x-6) + 1/(x^2+5)
both of those are easy to integrate, right?
Express the integrated as a sum of partial fractions and evaluate the integral
3x2+x+9/(x2+5)(x-6)
2 answers
We must be careful to insert parentheses when they are needed.
Expressions are evaluated according to the PEMDAS rule.
http://www.purplemath.com/modules/orderops.htm
For example, what you posted is mathematically equivalent
3x²+x +[9/(x²+5)]*(x-6)
which is (probably) not what you meant.
Correctly written, what you (probably) meant should read:
(3x2+x+9)/((x2+5)(x-6))
Here, we try to interpret correctly by guessing from context, but calculators are unforgiving with missing parentheses, that is why we need to develop the proper reflex for them.
Expressions are evaluated according to the PEMDAS rule.
http://www.purplemath.com/modules/orderops.htm
For example, what you posted is mathematically equivalent
3x²+x +[9/(x²+5)]*(x-6)
which is (probably) not what you meant.
Correctly written, what you (probably) meant should read:
(3x2+x+9)/((x2+5)(x-6))
Here, we try to interpret correctly by guessing from context, but calculators are unforgiving with missing parentheses, that is why we need to develop the proper reflex for them.