Asked by X
1. The length of a rectangle is twice its width. The perimeter of the rectangle is 24 inches. Write a system of equations in 2 variables. Use substitution to solve the problem.
A. Equation 1: L = 2W
L= 2(4) = 8
Equation 2: 2L + 2W = 24
2(2W) + 2W = 24
6W = 24
W = 24/6 = 4
(i would like help checking the Equations)
A. Equation 1: L = 2W
L= 2(4) = 8
Equation 2: 2L + 2W = 24
2(2W) + 2W = 24
6W = 24
W = 24/6 = 4
(i would like help checking the Equations)
Answers
Answered by
Bosnian
ERquation 1.
L = 2 W
2 W = L
Equation 2.
2 W + 2 L = 24
Substitution: 2 W = L
L + 2 L = 24
3 L = 24
L = 24 / 3 = 8 in
L = 2 W
8 = 2 W
8 / 2 = W
W = 4 in
L = 2 W
2 W = L
Equation 2.
2 W + 2 L = 24
Substitution: 2 W = L
L + 2 L = 24
3 L = 24
L = 24 / 3 = 8 in
L = 2 W
8 = 2 W
8 / 2 = W
W = 4 in
Answered by
naplan (COPY)
The answer is 16
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