Asked by alisha
Solve the system:4x+2y-13=0 and 3x=5y+26 by elimination.
3 (4x+2y-13=0)
12x+6y-26=0
4 (3x=5y+26)
12x=20y+104
I need to subtract since the signs are the same:
12x+6y-26=0
Since they don't match up, I'm having trouble subtracting them. I'm not sure what to do next. Please help??
3 (4x+2y-13=0)
12x+6y-26=0
4 (3x=5y+26)
12x=20y+104
I need to subtract since the signs are the same:
12x+6y-26=0
Since they don't match up, I'm having trouble subtracting them. I'm not sure what to do next. Please help??
Answers
Answered by
MathMate
3*(-13)=-39
so
12x+6y-39=0............(1)
change 4(3x=5y+26) to
4(3x-5y-26=0) =>
12x-20y-104=0 ...........(2)
(1)-(2)
26y+78=0
y=-3
Continue to solve for x, and check you answer by substitution.
so
12x+6y-39=0............(1)
change 4(3x=5y+26) to
4(3x-5y-26=0) =>
12x-20y-104=0 ...........(2)
(1)-(2)
26y+78=0
y=-3
Continue to solve for x, and check you answer by substitution.
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