Since no boric acid has been lost in dilution, we can use the standard equation:
C1V1=C2V2
where
C1=0.69,
V1=1000 mL
C2=0.50
Solve for V2.
Note: The amount of water to be added is V2-V1.
Michael has 1 liter of a mature containing 69%of boric acid. How much water must be added to make the mixture 50% boric acid ?
Represent answer as fraction.
1 answer