Asked by vikki
if a flask of 750 ml of 0.80m of nacl solution was left, and 275 ml evaporated, what is the new concentration
Answers
Answered by
MathMate
Since no NaCl was lost, we can use
C1V1=C2V2
C1=0.8 M
V1=750 mL
V2=(750-275)=475 mL
So
C2=C1V1/V2
=0.8*750/475
=1.26 mL
Note: I provide an extra significant figure when the first digit is "1". Your teacher may or may not recommend this.
C1V1=C2V2
C1=0.8 M
V1=750 mL
V2=(750-275)=475 mL
So
C2=C1V1/V2
=0.8*750/475
=1.26 mL
Note: I provide an extra significant figure when the first digit is "1". Your teacher may or may not recommend this.
Answered by
DrBob222
I want to point out to you that you need to find the caps key on your keyboard and use it. You may (or may not) know that m stand for molality and M stands for molarity. Two separate animals. My assumption is that you meant M = molarrity and MathMate worked it that way, also. I also note that MathMate made a typo. That's 1.26 M for the concentration of the resulting solution.
Answered by
MathMate
Thank you for pointing out the oversight, and the delicate case difference!
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