Asked by Tanzin
Your electric jug element produces 1.5kW of power. What is the minimum time it will take to heat 1.5L of water from 20 degrees Celcius to boiling
Answers
Answered by
bobpursley
heat=power*time
mc*deltaTemp=power*time
1.5kg*c*80C=1.5j/hr*timeinhours
so you need c in Joules/kgC
and solve for time in hours.
mc*deltaTemp=power*time
1.5kg*c*80C=1.5j/hr*timeinhours
so you need c in Joules/kgC
and solve for time in hours.
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