Question
Aluminum reacts with oxygen gas to produce aluminum oxide. How many moles of aluminum oxide would you expect to produce if you reacted 14.5 moles of oxygen gas with excess aluminum?
4Al +3O2 --> 2Al2O3
14.5 mol O2 x 4 mol Al / 3 mol O2 = 19.3 moles
4Al +3O2 --> 2Al2O3
14.5 mol O2 x 4 mol Al / 3 mol O2 = 19.3 moles
Answers
DrBob222
You have the right idea but the wrong numbers. You have calculated mols Al. You want mols Al2O3; the problem asks for mols Al2O3.
Sydney
14.5 mol O2 x 2 mol Al2O3 / 3 mol O2 = 9.67 moles.
Correct?
Correct?
DrBob222
yes