Question

(x/x-2)+(x-1/x+1)=-1

So far I was able to get it to x + (x-1) = -(x-2)(x+1) through cross multiplying, but I'm kinda lost with what to do now. Should I convert the right side to a polynomial and add the left side, then bring it all to 1 side so it = 0?

Thanks!

Answer 1

yes

Answer 2

Thanks. My problem from there is figuring out how to factor it.. I have x^2+x-3=0. Theres no factors of -3 that add up to 1.
-3+1 = -2
-1+3= 2
When i try to use the quadratic formula I end up with: (-1+/1(sqrt)13)/2

Am I missing something?

Answer 3

Totally incorrect.
First of all, I think you meant:
(x/(x-2))+((x-1)/(x+1)) = -1

then,

(x(x+1) + (x-1)(x-2) )/((x-2)(x+1) ) = -1
x^2 + x + x^2 - 3x + 2 = -x^2 + x +
2
3x^2 - 3x = 0
3x(x-1)=0
x=0 or x = 1

Answer 4

verification:
https://www.wolframalpha.com/input/?i=solve+(x%2F(x-2))%2B((x-1)%2F(x%2B1))%3D-1

Answer 5

Ahhh! That makes a lot more sense, thanks for the breakdown. I knew I was doing SOMETHING wrong haha. Thanks again :D