Total volume of solution:
= 40 cc + 50 cc
= 90 cc
Concentration of alcohohol:
= (volume of alcohol / total volume) × 100%
= _____ % alcohol
= 40 cc + 50 cc
= 90 cc
Concentration of alcohohol:
= (volume of alcohol / total volume) × 100%
= _____ % alcohol
Concentration = (volume of solute / volume of solution) x 100%
In this case, the solute is alcohol and the solution is a mixture of alcohol and water.
Given:
Volume of alcohol (solute) = 40 cm^3
Volume of water + alcohol (solution) = 150 cm^3
To find the concentration:
Concentration = (40 cm^3 / 150 cm^3) x 100%
Concentration = 0.267 x 100%
Concentration = 26.7%
Therefore, the concentration of the solution is 26.7%.
In this case, the amount of alcohol in the solution is 40 cm³, and the total volume of the solution is obtained by adding the volume of alcohol and the volume of water, which is 150 cm³.
Therefore, the concentration of the solution can be calculated using the following formula:
Concentration = (Amount of Solute / Total Volume) x 100
Substituting the values:
Concentration = (40 cm³ / (40 cm³ + 150 cm³)) x 100
Concentration = (40 cm³ / 190 cm³) x 100
Concentration ≈ 21.05%
So, the concentration of the solution is approximately 21.05%.