Two positive charges of 10micro column and 5micro column respectively are 12cm apart find the workdone in bringing them 6cm closer?

1 answer

work=PENew-PEold
= kqq/.12-kqq/.06

q is the charge on each of the charges or qq=50E-12

Of course, you could also realize the distance is being halved, so
work=2kqq/.12
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