Question

an ocean depth of 10.0 m, a drivers lung capacity is 2.40 l. the air temperture is 32.0n c and the pressure is 101.30 kpa.what is the volume of the drivers lungs at the same depth, at a temp of 21.0c and a pressure of 141.20 kpa?

Answer 1

(p1v1/t1) = (p2v2/t2)