mL1 x M2 = mL2 x M2
12 x 0.790 = 50 x M2
OR, since it's dilution, you start with 0.790M and multiply by a factor less than 1 like this
0.790 x 12/50 = ?
Technically, M2 is the concentration of Cu(NO3)2 but since 1 mol Cu = 1 mol Cu(NO3)2 it's all the same.
What formula would you use to solve this problem? I'm stuck.
You have prepared a solution by diluting 12.00mL of 0.790M copper(II) nitrate to a total volume of 50.00mL. What is the concentration of Cu2+ ions in the resulting solution? Report your answer to 3 decimal places.
2 answers
You have found that 14.37mL of 0.162M sulfuric acid reacts with exactly 20.00mL of barium hydroxide solution of unknown concentration. What is the molarity of the barium hydroxide solution? Round your answer to 3 decimal places and include units.
I know that this has something to do with Molarity and that the molarity equation is (M) = moles of solute / volume of solution (in liters) What I'm unsure of is how do set it up wit the unknown?
I know that this has something to do with Molarity and that the molarity equation is (M) = moles of solute / volume of solution (in liters) What I'm unsure of is how do set it up wit the unknown?