sin a cos b + cos a sin b = sin (a+b)
so what we really have is
sin(17x) = -.1
well there are an infinite number of solutions but just between 0 and 360 we have solutions in quadrants 3 and 4
sin of what = .1?
what = 5.8 degrees.
so5.8/17 = .34 degrees below + and - x axes
so x = 180.34 deg and x = - .34 deg
sin(6x)cos(11x)+cos(6x)sin(11x)=-0.1
solve for all solutions and provide steps so I can follow.. thank you
2 answers
since the period of sin(17x) is 360/17, there are 17 more pairs of solutions for x in [0,360) such that
17x = 180.34 + n*360 for n=0..17
17x = 359.66 + n*360
17x = 180.34 + n*360 for n=0..17
17x = 359.66 + n*360
1 answer