Asked by yeet
The equation $y = -6t^2 + 43t$ describes the height (in feet) of a projectile $t$ seconds after it is launched from the surface of Mars at 43 feet per second. In how many seconds will the projectile first reach 77 feet in height? Express your answer as a decimal rounded to the nearest tenth.
Answers
Answered by
Steve
huh? Just solve
-6t^2 + 43t = 77
-6t^2 + 43t = 77
Answered by
Anonymous
No one wants to solve it, steve
Answered by
Anonymous
(-3t + 11)(2t - 7) = roots t = 11/3, 7/2
Answered by
Anonymous
Bruh, steve you in first grade or something? Because you are nowhere near the correct answer
Answered by
Guy
Ya lol and he thinks hes a genius but hes in kindergarten
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