Asked by Shenaya

How do we find the value of(1.01)^5 approximately up to three decimals,only with the use of the Binomial theorem?

8 years ago

Answered by Anonymous

(1 + .01)^5 = 1^5 + 5(1)^4*.01 + (20/2)(1)^3*.01^2 etc

8 years ago

Answered by Shenaya

Thank you!

8 years ago

Answered by Anonymous

You are welcome.

8 years ago

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