Question

*Please check to see if overall values are put in the right place!*

Type of metal used= Copper
Mass of metal object= 72.5 g
Specific heat of copper= .385 J/g C°
Mass of empty styrofoam cup= 3.264 g
Mass of styrofoam cup & water= 142.3 g
Temp of water (before)= 23.1 C°
Temp of water (after)= 59.1C°

Questions: (See if the proper values are put in each depending on what it's asking)
1. change in temp of water (Tf-Ti) = 59.1C° - 23.1 C° = 36.0C°
2. Initial mass of water heated (mass of styrofoam cup & water minus mass of empty sytrofoam) = 142.3g - 3.264 = 139.0g
3. heat gained by the water= mass * change in temp * sp. ht= 72.5 g * 36.0 C° * .385 J/gC° = 1004.85
* for this one, the mass that it's asking for is the mass of copper right? I assume but i'm not sure? also, if this were the mass I'd use, in Proper Sig Figs, would the answer be 100.4?

4. calculate temp of hot metal object: heat lost by metal= heat gained by water
* I was confused on this one.

Calculations Table: (for this, I confused with what values would be used where or what would be subtracted from what. Any clarification would be helpful)
A. Change of temp of water = 36.0 C°
B. Mass of water (initial)= 139.0 g
C. Heat absorbed by water= ?
D. Temp of hot, metal object = ?
E. Temp of Bunsen burner flame = ?

Answer 1

For the most part, I have the correct values!

Answer 2

I'm not sure EXACTLY what you did.
1 is OK
2 is OK
3 is not right. The mass H2O is 139.0 g and q = mc(dT). You didn't use specific hrat H2O as far as I can see.
4. Apparently you are to calculate the initial T of the metal.
[mass Cu x specific heat Cu x (Tf-Ti)] + [mass H2O x specific heat H2O x (Tf=Ti)] = 0.
Tf for Cu is same as Tf for H2O.

A is OK
B is OK
C is the asnwer from 3.
D is calculated with the formula I gave you in r.
E. Can't answer. I don't know enough about what you did and I don't see enough information to calculate the flam T.