Question
The temperature is 66 degrees Fahrenheit. You drop a stone in a well. It hits water. You time this event: 4.6 sec. How deep is the well?
Answers
plumpycat
Temperature in Celsius:
= (5/9)(66 - 32)
= (5/9)(34)
= 18.9 ° C
Speed of sound at 18.9 ° C:
v = 331 + 0.6T
v = 331 + 0.6(18.9)
v = 342.3 m/s
Depth of well water surface:
= 342.3 m/s × 4.6 s ~ 1575 m
= (5/9)(66 - 32)
= (5/9)(34)
= 18.9 ° C
Speed of sound at 18.9 ° C:
v = 331 + 0.6T
v = 331 + 0.6(18.9)
v = 342.3 m/s
Depth of well water surface:
= 342.3 m/s × 4.6 s ~ 1575 m