Asked by ABC
The product of three consecutive integers is 21 more than the cube of smallest integer.the smallest integer is.A.-3 B.-4 C.-5 D.-6
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Answered by
Scott
x^3 + 3x^2 + 2x = x^3 + 21
3x^2 + 2x - 21 = 0
(3x - 7)(x + 3) = 0
x + 3 = 0
3x^2 + 2x - 21 = 0
(3x - 7)(x + 3) = 0
x + 3 = 0
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