Question
Different sizes of ribbon need to be cut to go around various shapes. All of the following sizes are in inches. √3 2√3 √5 (a) Without using your calculator, approximate the decimal equivalent of each number to the
nearest tenth. (b) Order the ribbon sizes from least to greatest
nearest tenth. (b) Order the ribbon sizes from least to greatest
Answers
plumpycat
√3:
3 is not a perfect square, but the nearest perfect squares are 1 and 4.
Thus √3 lies somewhere between √1 and √4.
Picture the numbers 1, 3 and 4 on a number line.
It takes 2 jumps to get from 1 to 3.
It takes 3 jumps to get from 1 to 4.
That means 3 is 2/3 of the way between 1 and 4.
So, we could estimate √3 to be 2/3 of the way between √1 and √4, or in other words, 2/3 of the way between 1 and 2.
1+ 2/3 = 1 2/3
To get this number to the nearest tenth, you would need to manually divide 2 by 3...or you might already know that 2/3 is 0.66666......
1 + 0.66666...... = 1.66666..... ~ 1.7 ( nearest tenth)
You can follow similar reasoning to find √5.
3 is not a perfect square, but the nearest perfect squares are 1 and 4.
Thus √3 lies somewhere between √1 and √4.
Picture the numbers 1, 3 and 4 on a number line.
It takes 2 jumps to get from 1 to 3.
It takes 3 jumps to get from 1 to 4.
That means 3 is 2/3 of the way between 1 and 4.
So, we could estimate √3 to be 2/3 of the way between √1 and √4, or in other words, 2/3 of the way between 1 and 2.
1+ 2/3 = 1 2/3
To get this number to the nearest tenth, you would need to manually divide 2 by 3...or you might already know that 2/3 is 0.66666......
1 + 0.66666...... = 1.66666..... ~ 1.7 ( nearest tenth)
You can follow similar reasoning to find √5.