Asked by Anonymous
Please help..
A wheel with radius 3 cm is being pushed up a ramp at a rate of 6 cm per second. The ramp is 730 cm long, and 150 cm tall at the end
A: Traveling at 6 cm/sec, how long does it take the wheel to complete one rotation?
B: What is the initial height of the center of wheel?
C:Traveling at 6 cm/sec, in one second, how much does the height of the center of wheel increase
D: Write an equation for the height of the center of the wheel as a function of t, time in seconds.
E: Write an equation for the height of the point P above the ground as a function of t, time in seconds
A wheel with radius 3 cm is being pushed up a ramp at a rate of 6 cm per second. The ramp is 730 cm long, and 150 cm tall at the end
A: Traveling at 6 cm/sec, how long does it take the wheel to complete one rotation?
B: What is the initial height of the center of wheel?
C:Traveling at 6 cm/sec, in one second, how much does the height of the center of wheel increase
D: Write an equation for the height of the center of the wheel as a function of t, time in seconds.
E: Write an equation for the height of the point P above the ground as a function of t, time in seconds
Answers
Answered by
Anonymous
it goes 2 pi r cm in one revolution
2 pi (3) = 6 pi cm in a revolution
6 pi cm (1 second/6 cm) = pi seconds per rev
B. 3 cm
C. 6 cm *150/730
D. (6 cm *150/730)t
I have no idea where point P is but it is the center height from part D + a sin or cos function of time depending on where it is on the wheel.
2 pi (3) = 6 pi cm in a revolution
6 pi cm (1 second/6 cm) = pi seconds per rev
B. 3 cm
C. 6 cm *150/730
D. (6 cm *150/730)t
I have no idea where point P is but it is the center height from part D + a sin or cos function of time depending on where it is on the wheel.
Answered by
Anonymous
I should be more specific about that sin or cos function arguement
sin or cos (2 pi t/T)
but we know that T is pi seconds
so
(2 t)
sin or cos (2 pi t/T)
but we know that T is pi seconds
so
(2 t)
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