Find the normal to the curve x=tt+1x=tt+1 and y=tt−1y=tt−1 at the point T where t = 2.

Question

I tried converting this into one equation (y=x(t+1)t−1y=x(t+1)t−1) but don't see how to get the answer which says:

dydx=−(t+1)2(t−1)2dydx=−(t+1)2(t−1)2
and that T=(23,2)T=(23,2), 3x−27y+52=03x−27y+52=0
I'd appreciate any pointers.

Answer 1

all that duplicated text is impossible to parse. Try typing it in, rather than copy/pasting.

Use t^2 for t squared

Answer 2

Find the normal to the curve
X=t÷[t+1] and Y=t÷[t-1]at point T where t=2.
I tried converting this into one equation Y=x(t+1)÷(t-1) but don't see how to get the answer which says:

dy÷dx=-(t+1)^2÷(t-1)^2
and that T=(2÷3,2), 3x−27y+52=0

Is this ok
Those problems i got are for an pdf i got from my sir

Answer 3

All the steps in your work are correct.