Asked by Shaniquaa
If the wavelength of an electron is equal to the radius of the n=2 orbit in He+, what must the velocity of the
electron be?
The answer is 6.88 x 10^6 m/s
How do I find this? I tried E = Z^2hcRh/n^2 and E= 1/2mv^2 with Z = 1, n=2, m=9.109E-31
electron be?
The answer is 6.88 x 10^6 m/s
How do I find this? I tried E = Z^2hcRh/n^2 and E= 1/2mv^2 with Z = 1, n=2, m=9.109E-31
Answers
Answered by
Shaniquaa
nevermind I got it
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