Asked by Marky

find the are bounded by the x-axis,y-axis and the curve x^2+y^2+16x+16y+64=0.
Answered by Steve
The area is bounded by 1/4 of the circle with center at (-8,8) and radius 8. So, it's just

r^2 - 1/4 (pi r^2) 64-(1/4)pi*8^2 = 64-16pi
There are no AI answers yet. The ability to request AI answers is coming soon!