Asked by Marky
what is the area of an equilateral triangle circumscribing a circle of radius 6cm.
Answers
Answered by
Damon
half triangle base = 6/tan 30
so base = b = 12/tan 30
sin 60 = h/b
so h = b sin 60
A=(1/2)bh
=(1/2)(12/tan30)(12/tan 30)sin 60
so base = b = 12/tan 30
sin 60 = h/b
so h = b sin 60
A=(1/2)bh
=(1/2)(12/tan30)(12/tan 30)sin 60
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