How many grams of ammonia are produced when 32g of nitrogen react with excess hydrogen?

N2 + 3H2 --> 2NH3

1 answer

for every mol of N (not N2) you get one mol of NH

mols of N = 32 g /14 g/mol = 32/14
so we get (32/14) mols of NH3

NH3 = 14+3 = 17 g/mol

so
(32/14)(17) grams
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