for every mol of N (not N2) you get one mol of NH
mols of N = 32 g /14 g/mol = 32/14
so we get (32/14) mols of NH3
NH3 = 14+3 = 17 g/mol
so
(32/14)(17) grams
How many grams of ammonia are produced when 32g of nitrogen react with excess hydrogen?
N2 + 3H2 --> 2NH3
1 answer