Asked by jay
How many grams of ammonia are produced when 32g of nitrogen react with excess hydrogen?
N2 + 3H2 --> 2NH3
N2 + 3H2 --> 2NH3
Answers
Answered by
Damon
for every mol of N (not N2) you get one mol of NH
mols of N = 32 g /14 g/mol = 32/14
so we get (32/14) mols of NH3
NH3 = 14+3 = 17 g/mol
so
(32/14)(17) grams
mols of N = 32 g /14 g/mol = 32/14
so we get (32/14) mols of NH3
NH3 = 14+3 = 17 g/mol
so
(32/14)(17) grams
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.