Asked by H
The distance from earth to the galactic centre is 23000 ly. What constant speed would be required to make the journey in 30 y of an astronaut's lifetime?
I know the answer should be 0.99999915c but don't know how to get there with time dilation or length contraction
I know the answer should be 0.99999915c but don't know how to get there with time dilation or length contraction
Answers
Answered by
Steve
1ly = 9.454254*10^15 m
1y = 3.1536*10^7 s
c = 2.99792*10^8 m/s
23000ly/30y
= (2.3*10^4 * 9.454254*10^15)/(30*3.1536*10^7)
= 2.298409*10^11 m/s
see what the Lorentz factor is for 0.99999915c and I'm sure it will work out.
1y = 3.1536*10^7 s
c = 2.99792*10^8 m/s
23000ly/30y
= (2.3*10^4 * 9.454254*10^15)/(30*3.1536*10^7)
= 2.298409*10^11 m/s
see what the Lorentz factor is for 0.99999915c and I'm sure it will work out.
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