z^4+z^2+1 = 0
(z^2-z+1)(z^2+z+1) = 0
one root is
z = (1+√3 i)/2 = cis(pi/3)
so, z^3 = -1
That means z^6 = 1
What is the smallest positive integer $n$ such that all the roots of $z^4 + z^2 + 1 = 0$ are $n^{\text{th}}$ roots of unity?
1 answer