Asked by Sandy
The area of a trapezoid is 720 cm square. The height is 10 cm. The two bases of the trapezoid are parallel. Find the length of each base, if one base is 3 times as long as the other.
Answers
Answered by
Reiny
area of trap
= (a+b)(h)/2, where a and b are the two parallel sides and h is the distance between them.
you have:
(x+3x)(10)/2 = 720
solve for x , then the bases are x and 3x
= (a+b)(h)/2, where a and b are the two parallel sides and h is the distance between them.
you have:
(x+3x)(10)/2 = 720
solve for x , then the bases are x and 3x
Answered by
Sandy
Thank you
Answered by
Sandy
Ok so is this correct?
20x + 60x= 720
80x=720
X=9 length of base
20x + 60x= 720
80x=720
X=9 length of base
Answered by
Reiny
no,
(x+3x)(10)/2 = 720
multiply both sides by 2
10(4x) = 1440
40x = 1440
x = 36
so the sides are 36 and 108
check:
area = (36+108)(10)/2
= 144(5) = 720 as required.
Time to review how to solve simple equations.
(x+3x)(10)/2 = 720
multiply both sides by 2
10(4x) = 1440
40x = 1440
x = 36
so the sides are 36 and 108
check:
area = (36+108)(10)/2
= 144(5) = 720 as required.
Time to review how to solve simple equations.
Answered by
Meryl
Hi can you help me how to find base and height of a trapezoid?
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