Asked by Alyssa
find an equation of the line tangent to the circle (x-1)^2+(y-1)^2=25 at the point (4,-3)
Can please someone explain this to me and show all work very confused
Can please someone explain this to me and show all work very confused
Answers
Answered by
Reiny
Find the derivative implicityl
2(x-1) + 2(y-1) dy/dx = 0
plug in (4,-3) , find dy/dx, which is the slope
Now that you have the slope and a point, use the method you learned to find the equation of the straight line
2(x-1) + 2(y-1) dy/dx = 0
plug in (4,-3) , find dy/dx, which is the slope
Now that you have the slope and a point, use the method you learned to find the equation of the straight line
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