Asked by Anonymous
A tube that is open on both ends is 4 meters long. Assuming that the speed of sound is 340m/s, find the following:
a) What is the wavelength of the fundamental standing wave (the first harmonic)
b) What is the frequency of the fundamental wave?
c) What is the frequency of the second harmonic?
a) What is the wavelength of the fundamental standing wave (the first harmonic)
b) What is the frequency of the fundamental wave?
c) What is the frequency of the second harmonic?
Answers
Answered by
Henry
a. Wavelength = 2 * 4m = 8 Meters.
b. Wavelength = V/F1 = 8m.
340/F = 8, F1 = ?.
F1 = Frequency of 1st harmonic.
c. F2 = 2 * F1.
b. Wavelength = V/F1 = 8m.
340/F = 8, F1 = ?.
F1 = Frequency of 1st harmonic.
c. F2 = 2 * F1.