Asked by girmay
Given an equation of circle(x-2)2+(y-3)2=25,find the equation of the image circle after a reflection about the line y=x+3
Answers
Answered by
Scott
the reflection is along a line through the center of the circle, perpendicular to the given line
slope of perpendicular is ... -1
equation of perpendicular
... y-3 = -1 (x-2) ... y = -x + 5
intersection with reflecting line
... (1,4)
center of reflected circle
... (0,5)
center has moved, but radius is the same
slope of perpendicular is ... -1
equation of perpendicular
... y-3 = -1 (x-2) ... y = -x + 5
intersection with reflecting line
... (1,4)
center of reflected circle
... (0,5)
center has moved, but radius is the same
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