Asked by Durbin23
When a solution of a certain gadolinium salt is electrolyzed with a current of 1.0 A for 2.0 h, 0.025 mol of Gd metal forms. Calculate the charge on the gadolinium ion in the salt.
Answers
Answered by
DrBob222
coulomhs = A x seconds = about 7,200.
96,485 coulombs will plate out, in grams, atomic mass Gd/#e = 157.25 g/#e.
grams Gd plated = 0.025 x 157.25 = about 3.93 grams.
atomic mass Gd/#e x 7,200/96,485 = 3.93
Solve for #e and I would round to the nearest whole number. My guess, for Gd, is for that to be +3 since Gd is a lanthanide element.
96,485 coulombs will plate out, in grams, atomic mass Gd/#e = 157.25 g/#e.
grams Gd plated = 0.025 x 157.25 = about 3.93 grams.
atomic mass Gd/#e x 7,200/96,485 = 3.93
Solve for #e and I would round to the nearest whole number. My guess, for Gd, is for that to be +3 since Gd is a lanthanide element.
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