Asked by Anonymous
How much heat is absorbed when a 35.0 g aluminum block increases in temperature from 23°C to 33°C?
Specific heat of Al: 0.900 J*g-1*°C-1
q=msΔT
q=(35.0 g)(.900)(33°C - 23°C)
q= 315 J? Just making sure there isn't anything that I am missing.
Specific heat of Al: 0.900 J*g-1*°C-1
q=msΔT
q=(35.0 g)(.900)(33°C - 23°C)
q= 315 J? Just making sure there isn't anything that I am missing.
Answers
Answered by
DrBob222
I didn't check the math on the calculator but the process and the numbers are correct.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.