Asked by jack
Assume that a procedure yields a binomial distribution with a trial repeated n=5n=5 times. Use some form of technology to find the probability distribution given the probability p=0.687 of success on a single trial.
Answers
Answered by
Scott
(s + f)^5
s^5 + 5 s^4 f + 10 s^3 f^2 +
... 10 s^2 f^3 + 5 s f^4 + f^5
s = p(success) = .687
f = p(failure) = 1 - p(success) = .313
s^5 + 5 s^4 f + 10 s^3 f^2 +
... 10 s^2 f^3 + 5 s f^4 + f^5
s = p(success) = .687
f = p(failure) = 1 - p(success) = .313
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