Asked by Camryn
Hi, I am in need of some help.
How would I find the derivative of the function:
f(x) = int e^sin(t) dt if the
upper bound is x^2 and the lower bound is cos(x)?
I'm not really sure what to do here since e^sin(t) is not an integratable function. Should I instead integrate the derivative of e^sin(t)?
How would I find the derivative of the function:
f(x) = int e^sin(t) dt if the
upper bound is x^2 and the lower bound is cos(x)?
I'm not really sure what to do here since e^sin(t) is not an integratable function. Should I instead integrate the derivative of e^sin(t)?
Answers
Answered by
Steve
it would be
e^(sin x^2)*2x - e^(cosx) * (-sinx)
This is just the chain rule via the back door.
If F(t) = ∫f(t) dt
then
∫[u,v] f(t) dt = F(v) - F(u)
Now take the derivative, remembering the chain rule.
e^(sin x^2)*2x - e^(cosx) * (-sinx)
This is just the chain rule via the back door.
If F(t) = ∫f(t) dt
then
∫[u,v] f(t) dt = F(v) - F(u)
Now take the derivative, remembering the chain rule.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.