it would be
e^(sin x^2)*2x - e^(cosx) * (-sinx)
This is just the chain rule via the back door.
If F(t) = ∫f(t) dt
then
∫[u,v] f(t) dt = F(v) - F(u)
Now take the derivative, remembering the chain rule.
Hi, I am in need of some help.
How would I find the derivative of the function:
f(x) = int e^sin(t) dt if the
upper bound is x^2 and the lower bound is cos(x)?
I'm not really sure what to do here since e^sin(t) is not an integratable function. Should I instead integrate the derivative of e^sin(t)?
1 answer