Asked by Anonymous
What effect does changing the function
f(x)=2sin(x2)−1 to the function
g(x)=2sin(x)−5 have on the graph of f(x)?
The graph is stretched vertically by a factor of 2 and shifted right 4 units .
The graph is compressed vertically by a factor of 2 and shifted left 4 units .
The graph is compressed horizontally by a factor of 2 and shifted down 4 units.
The graph is stretched horizontally by a factor of 2 and shifted up 4 units .
My answer is C
f(x)=2sin(x2)−1 to the function
g(x)=2sin(x)−5 have on the graph of f(x)?
The graph is stretched vertically by a factor of 2 and shifted right 4 units .
The graph is compressed vertically by a factor of 2 and shifted left 4 units .
The graph is compressed horizontally by a factor of 2 and shifted down 4 units.
The graph is stretched horizontally by a factor of 2 and shifted up 4 units .
My answer is C
Answers
Answered by
Reiny
assuming you meant f(x) = 2sin(x^2) - 1
look at the graphs of these two:
http://www.wolframalpha.com/input/?i=plot+y%3D2sin(x%5E2)%E2%88%921+,+y%3D2sin(x)%E2%88%925
none of the given answers are correct.
The problem is the x ---> x^2
There is compression, but at an accelerated rate for |x|?1
All your choices have the compression by a factor of 2
looking at the constants at the end, there is a vertical shift down 4 units, one of the choices has that
look at the graphs of these two:
http://www.wolframalpha.com/input/?i=plot+y%3D2sin(x%5E2)%E2%88%921+,+y%3D2sin(x)%E2%88%925
none of the given answers are correct.
The problem is the x ---> x^2
There is compression, but at an accelerated rate for |x|?1
All your choices have the compression by a factor of 2
looking at the constants at the end, there is a vertical shift down 4 units, one of the choices has that
Answered by
Anonymous
I'm so sorry!! I actaully meant f(x)=2sin(x/2)-1
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