3r=-6cosx

Question

I need help converting to rectangular form

also:change to polar co-ordinate form
3xy=5

Answer 1

Unusual to have an x in a polar form, was expecting
3r = -6cosØ , will assume that.

recall that cosØ = x/r
so
3r = -6x/r
3r^2 = -6x
x^2 + y^2 = -6x

for 3xy = 5
cosØ = x/r ---> x = rcosØ
and sinØ = y/r --> y = sinØ

3(rcosØ)(rsinØ) = 5
3r^2 sinØcosØ = 5