Question

A sinusoidal function whose frequency is 3, maximum value is 12, minimum value is −6 , and y-intercept is (0, 3) .

Which function could be the function described?



f(x)=9sin(6πx)+3

f(x)=9sin(x3)−3

f(x)=9sin(3x)+3

f(x)=9sin(6πx)−6 <my answer

Answer 1

almost. If the max is 12 and the min is -6 then the midpoint is at (12-6)/2 = 3

So, f(x)=9sin(6πx)+3

your choice has
max = -6+9 = 3
min = -6-9 = -15