Asked by rina
the ships leaves a port with a constant course and constant speed. after 2 hours the ship is 55miles south and 20 miles west of port. what is its course and speed?
Answers
Answered by
MathMate
Let x=east, y=north, then
the location of the ship after two hours is
(-20, -55)
Since it has constant course and speed, after one hour, it is at
(-10,-27.5)
The course is tan<sup>-1</sup>(-10/(-27.5)) west of south, and the speed is the distance travelled, using Pythatorean theorem,
s=sqrt(-10)²+(-27.5)²)
First try to understand the above calculations. If so, take out your calculator and find the answers. If not, please post any question you have.
the location of the ship after two hours is
(-20, -55)
Since it has constant course and speed, after one hour, it is at
(-10,-27.5)
The course is tan<sup>-1</sup>(-10/(-27.5)) west of south, and the speed is the distance travelled, using Pythatorean theorem,
s=sqrt(-10)²+(-27.5)²)
First try to understand the above calculations. If so, take out your calculator and find the answers. If not, please post any question you have.
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