Question

1. The first order rate constant for the reaction, SO2Cl2(g) → SO2(g) + Cl2(g), is 2.20 x 10-5 s-1 at 593 K. What percent of a sample of SO2Cl2 would be decomposed by heating at 593 K for (a) 1 hr, (b) 3 hr. How long will it take for half of the SO2Cl2 to decompose?

Answer 1

ln(No/N) = kt
(c) part.
Let No = 100 to start.
then N = 50 at end.
ln(100/50) = 2.2E-5*t
0.693 = 2.2E-5*t and
t = about 30,000 hours but that's just a close estimate. You should get a better answer. Post your work if you have problems.

Answer 2

Ka re nahi aa raha hai. Ka karta hai.