Asked by Anonymous

The oxidation number of sulphur in CuSO4.5H2O is ......
Answered by DrBob222
Cu is +2
S is S
O is -2. 4*-2 = -8
All compounds add to zero.
Cu + S + 4*-2 = 0
2 + S +(-8) = 0
2 + S + -8 = 0
Solve for S.
S = 0 - 2 + 8 = ?
Answered by The oxidatin
10
Answered by Robel
R7o3b6e2l5
Answered by Robel
0973625793
Answered by Samuel Ashenafi
+6 because SO4 has no bracket
Answered by Esrom
The oxidizing agent is oxizided by the reduced agent
Answered by kabtam
Ansewor
Answered by Mulualem
What about Hydrogen
Answered by Mulualem
What about Hydrogen
Answered by [email protected]
CuSo4,5H2O
Cu=+2
O=-2*4 =-8
+2+x-8+2-2=0
X=+6
Answered by bura
6
Answered by Bot
The oxidation number of sulphur in CuSO4.5H2O is +6.