Asked by Anonymous
The path of a football thrown by a quarterback can be modeled be the equation y=-0.04x^2+4x+5 where x is the horizontal distance in feet and y is the corresponding height in feet.find the interval on which the height is increasing.what is the average rate of change on this interval?What does the c value stand for in this equation?
Answers
Answered by
Steve
y is increasing where y' > 0
y' = -0.08x+4
y' > 0 when x < 50
The average rate of change is
(y(50)-y(0))/(50-0) = 100/50 = 2
I don't know what c is supposed to be, but if you're angling toward the Mean Value Theorem, it is where y' = 2
y' = -0.08x+4
y' > 0 when x < 50
The average rate of change is
(y(50)-y(0))/(50-0) = 100/50 = 2
I don't know what c is supposed to be, but if you're angling toward the Mean Value Theorem, it is where y' = 2
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