Asked by Alice
Hello! I am struggling with this problem:
Find the Taylor Series for sin(x-2) centered at c=3.
My work so far:
sin(1)+(x-3)cos(1)-(1/2)(x-3)^2sin(1)-(1/6)(x-3)^3cos(1)+(1/24)(x-3)^4sin(1)...
I know that the Taylor series for sign is typically: the summation from n=0 to infinity of ((-1)^n)/((2n)!) (x-c)^2n
I would appreciate any help! Thanks!
Find the Taylor Series for sin(x-2) centered at c=3.
My work so far:
sin(1)+(x-3)cos(1)-(1/2)(x-3)^2sin(1)-(1/6)(x-3)^3cos(1)+(1/24)(x-3)^4sin(1)...
I know that the Taylor series for sign is typically: the summation from n=0 to infinity of ((-1)^n)/((2n)!) (x-c)^2n
I would appreciate any help! Thanks!
Answers
Answered by
Steve
looks good to me.
Of course, the series is
∞
∑ 1/k! f<sup><sup>(k)</sup></sup> (x-2)<sup><sup>k</sup></sup>
The (2n)! series is for cos(x)
k=0
Of course, the series is
∞
∑ 1/k! f<sup><sup>(k)</sup></sup> (x-2)<sup><sup>k</sup></sup>
The (2n)! series is for cos(x)
k=0
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