Asked by Lizzy B
Okay I've got a HUGE chem test tomorrow and I desperately need help! Please help!!!!
73. Hematite (Fe2O3) and magnetite (Fe3O4) are two ores used as sources of iron. Which ore provides the greatest percentage of iron per kilogram?
78. A hydrate contains .050 mole of H2O to every .00998 mole of ionic compound XYY the formula of the hydrate XY.
79. Calculate the mass of the water of hydration if a hydrate looses .025 mole of H2O when heated.
I absolutely have no idea how to start any of these, please help!
73. Hematite (Fe2O3) and magnetite (Fe3O4) are two ores used as sources of iron. Which ore provides the greatest percentage of iron per kilogram?
78. A hydrate contains .050 mole of H2O to every .00998 mole of ionic compound XYY the formula of the hydrate XY.
79. Calculate the mass of the water of hydration if a hydrate looses .025 mole of H2O when heated.
I absolutely have no idea how to start any of these, please help!
Answers
Answered by
DrBob222
73. Because this is chemistry you're intimidated. % anything = (mass of that/total mass)*100
%Fe in Fe2O3 = (2*atomic mass Fe/molar mass Fe2O3)*100 = ?
Works the same way for Fe3O4.
78. Sorry, I don't understand this one. Neither XYY nor XY makes sense to me. Read that sentence; something seems to be missiing. My guess; however, is that you want to know the formula of the hydrate and that is 1 mol compound:Y mols H2O. To get that 0.05mols/0.00998 - 5.01 mols H2O which rounds to 5.0. So the formula is, for example, CuSO4.5H2O which is in the ration of 1 mol salt to 5 mol H2O.
79.
So it loses 0.025 mols H2O. Convert that to grams H2O. g = mols x molar mass = ?
%Fe in Fe2O3 = (2*atomic mass Fe/molar mass Fe2O3)*100 = ?
Works the same way for Fe3O4.
78. Sorry, I don't understand this one. Neither XYY nor XY makes sense to me. Read that sentence; something seems to be missiing. My guess; however, is that you want to know the formula of the hydrate and that is 1 mol compound:Y mols H2O. To get that 0.05mols/0.00998 - 5.01 mols H2O which rounds to 5.0. So the formula is, for example, CuSO4.5H2O which is in the ration of 1 mol salt to 5 mol H2O.
79.
So it loses 0.025 mols H2O. Convert that to grams H2O. g = mols x molar mass = ?
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