Asked by Maddiey

The length of a rectangle is
4 in longer than its width. If the perimeter of the rectangle is 48 in, find its area.
Answered by Ms. Sue
Now it's your turn.

I'll be glad to check your answer.
Answered by Maddiey
would I set it up like this:


48=4(4w+w)

?????
Answered by Maddiey
wait no... wouldn't it be 48+2(4w+w)???
Answered by Maddiey
48 equals 2(4w+w) not plus...
Answered by Ms. Sue
Close.

48 = 2(W + W + 4)
48 = 4W + 8
40 = 4W
10 = W
Answered by Bosnian
L = W + 4

P = 2 W + 2 L = 2 ( W + L ) = 48

2 ( W + W + 4 ) = 48

2 ( 2 W + 4 ) = 48 Divide both sides by 2

2 W + 4 = 24 Subtract 4 to both sides

2 W + 4 - 4 = 24 - 4

2 W = 20 Divide both sides by 2

W = 10 in


L = W + 4 = 10 + 4 = 14 in


A = L * W = 10 * 14 = 140 in ^ 2