Question

Three particles have charges +20μC each.They are fixed at the corners of an equilateral triangle of side 0.5m .The force on each of particle has magnitude
The force on each of particle has magnitude... no kidding.

The force will be along the directions of the sides, due to symettry.

Each of the two forces on a charge is
kqq/.5^2
but we want only the compoent in the direction of the angle bisector, which is 30 deg from each side. Therefore, net force on each corner is
2kqq/.5^2 * cos30

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