Question

195x^5 + 168x^4 - 28x^3 - 24x^2



This is factoring I have looked at everything.

Answer 1

I need help working it out. This is poloynomials.

Answer 2

Well, let's look at everything again.

clearly x^2 is a common factor.
Look at the numbers, start with the 24
24 = 3*8 = 3*2*2*2
so the 195 is only divisible by 3 but not 28, so
the HCF is x^2

195x^5 + 168x^4 - 28x^3 - 24x^2
= x^2(195x^3 + 168x^2 - 28x - 24)

Answer 3

The x^2 is easy:

195x^5 + 168x^4 - 28x^3 - 24x^2
x^2(195x^3+168x^2-28x-24)

Now things get tough. If there are any rational roots of the form p/q, then we know that

p divides 24
q divides 195

Some time and effort should convince you that there are no other rational roots, so no factors using integers.