Question

The base of a right prism is isosceles trapezoid with legs c=d = 5 cm, bases a=8 cm and b=14 cm, and altitude of the trapezoid k=4 cm. The height of the prism h=10 cm. Find:

Lateral area
I made a rough sketch.
For the total surface area I see two equal trapezoids, and 4 rectangles.
the rectangles are:
14 by 10 , 8 by 10 and 2 of 5 by 10

the area of the trapezoid = (1/2)(8+14)/2

finish the arithmetic and use the correct units
320
Wrong
The answer is 408!!!
The area of the two trapezoids: 4(8+14)=88
area of the two leg rectangles: 5*10*2=100
area of base one: 8*10=80
area of base two: 14*10=140
total: 88+100+80+140= 408 cm Squared.
That is the surface area you noob!
460
its 104
It’s 320
Its 104 I PROMISE U PEEPS
It is 320!
its not 320!
It is 320, I tested it. (On my hw)
LOL the answer is 408 for surface area but not lateral area :D
104!!

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