Asked by Katniss Everdeen

The base of a right prism is isosceles trapezoid with legs c=d = 5 cm, bases a=8 cm and b=14 cm, and altitude of the trapezoid k=4 cm. The height of the prism h=10 cm. Find:

Lateral area
Answered by Reiny
I made a rough sketch.
For the total surface area I see two equal trapezoids, and 4 rectangles.
the rectangles are:
14 by 10 , 8 by 10 and 2 of 5 by 10

the area of the trapezoid = (1/2)(8+14)/2

finish the arithmetic and use the correct units
Answered by Anonymous
320
Answered by Anonymous
Wrong
Answered by Anonymous
The answer is 408!!!
Answered by Anonymous
The area of the two trapezoids: 4(8+14)=88
area of the two leg rectangles: 5*10*2=100
area of base one: 8*10=80
area of base two: 14*10=140
total: 88+100+80+140= 408 cm Squared.
Answered by Anonymous
That is the surface area you noob!
Answered by Anonymous
460
Answered by Anonymous
its 104
Answered by Sofiya
It’s 320
Answered by HEHE
Its 104 I PROMISE U PEEPS
Answered by magentastar
It is 320!
Answered by idk
its not 320!
Answered by HEHE
It is 320, I tested it. (On my hw)
Answered by Advika M
LOL the answer is 408 for surface area but not lateral area :D
Answered by Anonymous
104!!
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