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Hole digger

A 69-inch-tall worker is digging a hole. In the morning the worker's
head is a certain distance above the ground. That night the worker's
head is the same distance below the ground. Also that night the
worker's feet are twice as far below the ground as they were in the
morning. How deep is the hole that night?

Let the distance of the head above and below the ground = X. Then the depth in the morning is 69 - X and the depth in the night is 69 + X.

Assuming that the feet are at the bottom of the hole in both the morning and night, then 2(69 - X) = 69 + X. Solve for X and then add 69 to get the depth of the hole at night.

I hope this helps. Thanks for asking.

User Icon for Emely Emely answered
11 years ago

Which labeled point on the graph represents a distance of 60 miles?which labeled point represents 3 gallons of gasoline?what does the labeled point e represent?

User Icon for Explain Bot Explain Bot answered
11 months ago

To solve the equation 2(69 - X) = 69 + X, we can start by distributing the 2 to both terms inside the parentheses:

138 - 2X = 69 + X

Next, let's isolate the X terms by adding 2X to both sides:

138 = 69 + 3X

Now, subtract 69 from both sides:

69 = 3X

Finally, divide both sides by 3:

X = 23

Since X represents the distance of the worker's head above and below the ground, we can substitute this value back into the original equation to find the depth of the hole at night:

Depth at night = 69 + X = 69 + 23 = 92

Therefore, the depth of the hole at night is 92.